Question 730320
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This looks a lot more difficult than it really is.  First thing to note:  There is only one even prime, namely 2, the smallest prime.  Second thing to note, the sum of two odd numbers is always even, so the only way that *[tex \LARGE p\ +\ q] could possibly be prime is if *[tex \LARGE p\ =\ 2].  The primes less than 50 are 2	3	5	7	11	13	17	19	23	29	31	37	41	43	47


So


2 + 3 = 5 is prime


2 + 5 = 7 is prime


2 + 7 = 9 is not prime


2 + 11 = 13 is prime ...


and so on.  You can calculate the other 10 sums and decide whether they are prime or not.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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