Question 729024
log[8](x+2)=2-log[8](2)
{{{log(8,(x+2))=2-log(8,(2))}}}
{{{log(8,(x+2))+log(8,(2))=2}}}
{{{log(8,(x+2)*(2))=2}}}
convert to exponential form:
base(8) raised to log of the number(2)=number((x+2)*(2)
8^2=2x+4
64=2x+4
2x=60
x=30