Question 730090
Solve each system using the elimination method:

x - 3y = -7 (Equation 1)

2x = 6y - 14 (Equation 2)


From Equation 1:

x - 3y = -7

Add 3y to each side of the equation:

x - 3y + 3y = -7 + 3y

Therefore:

x = -7 + 3y

Substitute x = -7 + 3y into Equation 2.

Equation 2:

2x = 6y - 14

2(-7 + 3y) = 6y - 14

-14 + 6y = 6y - 14

Add 14 to each side of the equation.

We remain with:

6y = 6y

y = 0



Substitute y = 0 into Equation 1:

x - 3y = -7

x - 3(0) = -7

x - 0 = -7

Add 0 to each side of the equation:

Therefore:

x = -7



Answer:


x = -7 and

y = 0




Lennox Obuong
Algebra Tutor
Nairobi, Kenya