Question 730182
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function. Is the vertex a maximum or minimum? 
y=x^2-3x+2
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Standard form of equation for a parabola(sometimes referred to as the vertex form):
y=A(x-h^2+k, (h,k)=(x,y) coordinates of the vertex. A is a multiplier which affects the slope or steepness of the curve. If A>0, the parabola opens up and has a minimum. If A<0, the parabola opens down and has a maximum. The y-coordinate of the vertex is the maximum or minimum value occurring at the x-coordinate of the vertex.
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For given equation:y=x^2-3x+2
complete the square:
y=(x^2-3x+9/4)-9/4+2
y=(x-3/2)^2-1/4
A=1, so parabola opens up and has a minimum at coordinates of the vertex
vertex: (3/2,-1/4)
Axis of symmetry: x=3/2

See graph below as a visual check:

{{{ graph( 300, 300, -5, 5, -5, 5, x^2-3x+2) }}}