Question 730135
<pre>
That's the same as the binomial probability of getting exactly x=10 successes
out of n=35 trials with a probability of 1 success in 1 trial being p={{{1/3}}}. 

The p={{{1/3}}} probability comes from the fact that there are 2 rolls, "1" and "2",
out of the 6 possible rolls that are less than or equal to 2, and {{{2/6}}} reduces to {{{1/3}}}.      

The formula for the binomial probability of getting exactly x successes
in n trials with a probability of p of 1 success in 1 trial is:

C(n,x)p<sup>x</sup>(1-p)<sup>n-x</sup>

Our case is n=35, x=10, p={{{1/3}}}.

Substituting those gives 0.1231203703

Rounding to four decimal places: 0.1231

Edwin</pre>