Question 730156
The {{{center-radius}}} form of the circle equation is in the format {{{(x-h)^2 + (y-k)^2 = r^2}}}, with the center being at the point ({{{h}}}, {{{k}}}) and the radius being "{{{r}}}".


{{{25x^2+25y^2=25 }}}....both sides divide by {{{25}}}


{{{25x^2/25+25y^2/25=25/25 }}}

{{{x^2+y^2=1 }}}....compare to {{{(x-h)^2 + (y-k)^2 = r^2}}} and you see that ({{{h}}}, {{{k}}})=({{{0}}}, {{{0}}}) and  {{{r=1}}}

{{{ graph( 600, 600, -2, 2, -2,2, x^2+y^2<=1) }}}