Question 64007
Can you Solve the following 2 equation: 
x^2e^x-5xe^x=0
Factor to get:
xe^x(x-5)=0
x=0 or e^x=0 or x-5=0
x=0 or x=5
Note e^x is never zero
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5^3x=5^(4x-2)
3x=4x-2
x=2
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Cheers,
Stan H.