Question 730008
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Set *[tex \LARGE y] equal to zero, then solve for the *[tex \LARGE x]-coordinate of the *[tex \LARGE x]-intercept.  Note the sign.  Set  *[tex \LARGE y] equal to zero, then solve for the *[tex \LARGE x]-coordinate of the *[tex \LARGE x]-intercept.  Note the sign. If the two signs are positive, then yes, the graph passes through the first quadrant.  If they are both negative or zero, then the graph does NOT pass through the first quadrant.


Another way to look at it is to examine the sign on the slope.  If positive, then the graph always passes through the first quadrant.  If negative, it only passes through the first quadrant if the *[tex \LARGE y]-coordinate of the *[tex \LARGE y]-intercept is positive.


Extra credit:  Does *[tex \LARGE y\ =\ -x] pass through Quadrant I? 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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