Question 729991
System:
 xy=-12
         x-2y+14=0


No need to be stuck.  More than one way to go.

{{{xy=-12}}}, gives you {{{y=-12/x}}}.  Substitute into other equation.
{{{x-2(-12/x)+14=0}}}
{{{x+24/x+14=0}}}
{{{x^2+24+14x=0}}}
{{{x^2+14x+24=0}}} and solve for x from this.
...


Watch for a possible extraneous value for x, although most likely not important since this is not really an application problem.