Question 729921
Mean height of women in a country aged 20-29 is 64.2 inches. 
A random sample of 60 women in this age group is selected 
What is the probability that the mean height for the sample is greater than 65 inches if the standard deviation is 2.54 
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z(65) = (65-64.2)/[2.54/sqrt(60)] = 0.8/(0.3279) = 2.44
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P(x-bar > 65) = P(z > 2.44) = 0.0073
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Cheers,
Stan H.