Question 729726
Better if you know how to do synthetic division, but you can still use polynomial division to find binomial factors according to Rational Roots Theorem.  There are a few choices to try for binomial factors, but the successful ones will be (x-2) and (x+2).  You will be able to factor the polynomial into this equation:

 
{{{highlight((x-2)(x+2)(x^2-6x+1)=0)}}}.  The roots (or zeros) are +2, -2, 3+2*2^(1/2), 
and 3-2*2^(1/2).  The non-factorable quadratic factor has irrational roots.