Question 729742
Find the x & y intercept points by plugging x=0,y=0 in both equations.								
y=3x+6.........................(1)
y=-x-2..........................(2)



equation I								
when x=	0	y=	6	,(	0	,	6	)
when y =	0	x=	6	,(	-2	,	0	)
Equation 2								
when x=	0	y=	-2	(	0	,	-2	)
when y =	0	x=	-2	(	-2	,	-0	)
								
{{{drawing(300,300,-10,10,-10,10,circle(0,6,0.3),circle(-2,0,0.3),circle(0,-2,0.3),circle(-2,0,0.3),graph(300,300,-10,10,-10,10,y=3x+6,y=-x-2))}}}								
								
You will observe that the point of intersection is						-2,0
The solution of the system is	(  	-2	,	0	)