Question 729680
 Solve. Log base 8 of 2x + log base 8 of 5 = 1
{{{log(8,2x) + log(8,5)}}} = 1
addition of logs is multiply
{{{log(8,2x*5)}}} = 1
{{{log(8,10x)}}} = 1
The exponent equiv
{{{8^1}}} = 10x
or
10x = 8
x = 8/10
x = .8