Question 729600
First car	40	mph				
Car II	90	mph				
First car		09:00				
Car II		10:00				
Difference in time=		01:00	=>	1.00	hours	
First car	will have covered	40.00	miles		Car II	starts
catch up distance=		40.00	miles			
catch up speed =		90	-40			
catch up speed =		50	mph			
Catchup time = catchup distance/catch up speed						
catch up time=		0.8				
catch up time=		0.80	hours	=48 minutes		
They will meet at		10:48	pm