Question 729566
729566 (2013-03-23 01:27:51): X3 - 3X2 + 4 = 0		or x^3-3x^2+4=0		
arrange the equation as	x^3-4x^2+4x+x^2-4x+4	take first three terms together & second three terms together		
		(x^3-4x^2+4x)+(x^2-4x+4)=0		
		x(x^2-4x+4)+(X^2-4x+4)=0		
		x(x-2)^2+(x-2)^2=0	(identity a^2-2ab+b^2=(a-b)^2  )	
		(x-2)^2(X+1)=0		
		either (x-2)^2=0 or (x+1)=0		
		(x-2)^2=0	(x-2)=0	x=2,2
		(x+1)=0	x=-1	
		x=2 ,2 ,-1 are the solutions