Question 729391
Assume 
7 sin2(x) − 6 cos2(x) = 1
Find the numerical value of 
sin2(x)
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7sin^2x-6cos^2x=1
7sin^2x-6(1-sin^2x)=1
7sin^2x-6+6sin^2x)=1
13sin^2x=7
sin^2x=7/13