Question 729461

If we start with an even number and each number in the sequence is {{{2}}} more than the previous number then we will get {{{consecutive}}}{{{ even}}}{{{ integers}}}.

 Let {{{x}}} be first even number, than {{{x + 2 }}} is second and {{{x + 4}}} third consecutive number.

Their sum is:

{{{x+(x+2)+(x+4)=408}}}...solve for {{{x}}}


{{{x+x+2+x+4=408}}}

{{{3x+6=408}}}

{{{3x=408-6}}}

{{{3x=402}}}

{{{x=402/3}}}

{{{x=134}}}.....first even number

{{{x+2=136}}}.....second even number

{{{x+4=138}}}.....third even number

so,the largest of the three integers is {{{138}}}