Question 63861
Final velocity = Initial velocity + Acceleration x time
or mathematically
v = u + at
25 = 13 + 6a
25 - 13 = 13 + 6a - 13
12 = 6a
a = 2 m/s^2 

{{{v^2 = u^2 + 2as}}} S = the displacement (distance)
{{{25^2 = 13^2 + 2*2*s}}}
{{{625 = 169 + 4*s}}}
{{{625 - 169 = 169 + 4*s - 169}}}
{{{456/4 = 4*s/4}}}
distance = 114 metres