Question 729297
Logarithms have a rule which tells us, {{{p*ln(a)=ln(a^p)}}}.  With that rule applied on {{{0.5ln(100)-2ln(x)+8ln(y)}}}, we can say this:


{{{ln(100^0.5)-ln(x^2)+ln(y^8)}}}.


Logarithms have a rule which tells us, {{{log(b,mn)=log(b,m)+log(b,n)}}} and {{{log(b,(m/n))=log(b,m)-log(b,n)}}}.  We can apply that rule to say this:


{{{highlight(ln((100^0.5)(y^8)/(x^2)))}}}