Question 729248
A = P(1+r)^t


A = 4000(1+0.49)^t


A = 4000(1.49)^t


A = 4000(1.49)^24


A = 4000(14,337.4013230579)


A = 57,349,605.2922316


So that's the rough number of bacterium that will be present in 24 days