Question 728889
(4x^2)+bx-3=0 solve for b. and one solution is -5/2

if p & q are the roots of the equation

p+q=-b/4

let p=-5/2

(-5/2)+q=-b/4
multiply by 4
-10+4q=-b...................(1)

p*q=-3/4

(-5/2)q=-3/4

q=3/10

plug q in (1)
-10+4(3/10)=b

(-100+12)/10=b

-88/10 =b
-44/5 = b