Question 728839

The given line 2x+y=1 or 2x+y-1=0		
Slope of this line=-coefficient of x/coefficient of y		
slope=-2/1=-2		
		
The line passing thr(-3,1) has slope=m=-2		
		
using point-slope form		
		
y-y_1=m(x-x_1)	here y_1=1 &x_1=-3	
		
y-1=-2*((x-(-3))		
		
y-1=-2x-6		
		
y+2x+6-1=0	Changing sides	
2x+y+5=0	slope of this line=-2 & it passes thr(-3,1) i.e.2*(-3)+1+5=0	
		
2x+y+5=0 is the equation of line parallel & passing thr(-3,1)