Question 728827
Exponential-and-logarithmic-functions/728827 (2013-03-20 22:51:59): 

10^(a)=1.1(10^(5))		
Now given argument is
		
10^(a)=1.1(10^5)
		
taking log on both sides
		
Log{10^(a)}=log(1.1)+{log(10^5)}
		
a*log(10)=log(1.1)+5*log(10)		(log10=1)

a*1=.041392+5*1		l0g(1.1)=0.041392

a=5.041392
		
10^5.041392=110000	&  1.1(10^5)=1.1*100000=110000