<PRE><B>Question 728826</B>
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Because *[tex \LARGE (3x\ -\ 4)^2\ \neq\ 9x^2\ -\ 16]


*[tex \LARGE \ \ \ \ \ \ \ \ \ (3x\ -\ 4)^2\ = (3x\ -\ 4)(3x\ -\ 4)\ =\ 9x^2\ -\ 12x\ -\ 12x\ +\ 16\ =\ 9x^2\ -\ 24x\ +\ 16]


And furthermore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ 9x^2\ -\ 16\ =\ (3x\ -\ 4)(3x\ +\ 4)\ \neq\ (3x\ -\ 4)(3x\ -\ 4)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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