Question 728811
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Yes, the ratio of the measure of the longer chord to the measure of the shorter chord is equal to the ratio of the measure of the shorter perpendicular to the longer perpendicular, in other words:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{26}{24}\ =\ \frac{x}{6}]


Which is equivalent to the proportion you had (once the typo was corrected) since you can interchange the means on a proportion.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{26}{x}\ =\ \frac{24}{6}]



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{26}{x}\ =\ 4]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{26}{4}\ =\ 6.5]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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