Question 728706
First you would take the second equation and move the 5x to the right side by subtracting 5x on both sides. You should now have -y=-5x+13. To make y positive, we need to divide this equation by -1. You should now have y=5x-13. Substitute y=5x-13 in the first equation. {{{2x+3(5x-13)=12}}} = {{{2x+15x-39=12}}}. Add the x values and you have 17x-39=12. Now we need to move the 39 to the right side by adding 39 on both sides. Now you should have {{{17x=51}}}. Divide 17 on both sides to get x, and you should get {{{x=3}}}. To find y, you would plug x in the second equation. {{{5(3)-y=13}}} = {{{15-y=13}}}. Then move the 15 by subtracting it on both sides to get y by it self. You should now have -y = -2. To find y, divide both sides by -2, and you should get {{{y=2}}}. So x=3 and y=2. I hope this helped! Good luck!