Question 728614

the point-slope of the equation {{{y+10=6(x-2)}}} will be

 {{{y=6(x-2)-10}}}

 {{{y=6x-12-10}}}

{{{y=6x-22}}} where slope is {{{6}}} and {{{y-intercept}}} is at point ({{{0}}},{{{-22}}})


{{{ graph( 600, 600, -10, 10, -25, 10, 6x-12-10) }}}