Question 728599
The {{{x-intercepts}}} are where the graph crosses the {{{x-axis}}}, and the {{{y-intercepts}}} are where the graph crosses the y-axis.

Then, algebraically,

    an {{{x-intercept}}} is a point on the graph where {{{y =0}}}, and
    a {{{y-intercept}}} is a point on the graph where {{{x =0}}}

so, 

{{{2x+6y=11}}} ...if {{{y =0}}}

{{{2x+6*0=11}}}

{{{2x=11}}}

{{{x=11/2}}}

{{{x=5.5}}}

the {{{x-intercept}}} is at point ({{{5.5}}},{{{0}}})

now find {{{y-intercept}}}

{{{2x+6y=11}}} ...if {{{x =0}}}

{{{2*0+6y=11}}}

{{{6y=11}}}

{{{y=11/6}}}

{{{y=1.833}}}

the {{{y-intercept}}} is at point ({{{0}}},{{{1.833}}})


{{{drawing( 600, 600, -10, 10, -10, 10,circle(0,1.833,0.2),circle(5.5,0,0.2), graph( 600, 600, -10, 10, -10, 10, (-1/3)x+11/6)) }}}