Question 728569
from 
[x^2+6x+6/(x^2+5x-24)]=[(78/(x^2+5x-24)]
we get
(x^2+6 x+6)/((x-3) (x+8)) = 78/((x-3) (x+8))

(x^2+6 x-72)/((x-3) (x+8)) = 0
((x-6) (x+12))/((x-3) (x+8)) = 0
x=6 
x=-12