<PRE><B>Question 728509</B>
Write a quadratic equation having the given numbers as solutions. 
8/5, 5/3 
Possible answers:
f(x) = k(5x-8)(3x-5)
f(x) = k(5x^2-49x+40)
Let k = (3/5)
Then 
f(x) = 3x^2 - (3/5)49x + (3/5)40
f(x) = 3x^2 - 29.4x + 24
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Comment:  The optional answers do not match the posted problem.
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Cheers,
Stan H.
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A) 3x2 -40x + 25=0
B) 3x2 + 25x + 40=0
C) 3x2 + 49/5x + 8=0
D) 3x2 -49/5x + 8=0
E) 3x2 + 40x + 25=0
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