Question 728441
1. 
{{{e^-6c^3=(1/e^6)c^3=c^3/e^6}}}

2.
{{{2y^-9h^2(2y^0h^-4)^-6}}}


={{{2(1/y^9)h^2(2*1*(1/h^4))^-6}}}


={{{(2h^2/y^9)*((1/(2/h^4)))^6}}}


= {{{(2h^2/y^9)*1/(2^6/h^24)}}}


= {{{(cross(2)h^2/y^9)/(cross(64)32/h^24)}}}


= {{{(h^24*h^2)/32y^9}}}


= {{{h^26/32y^9}}}