Question 728367
x = 3 - i (given) or x = 3 + i (all complex roots come in conjugate pairs)


x - 3 = -i or x - 3 = i


(x - 3)^2 = (-i)^2 or (x - 3)^2 = i^2


(x - 3)^2 = i^2 or (x - 3)^2 = i^2


(x - 3)^2 = i^2


(x - 3)^2 = -1


(x - 3)^2 + 1 = 0   ----> Equation in Vertex Form: {{{y = (x-3)^2 + 1}}}

(x - 3)(x - 3) + 1 = 0


x^2 - 6x + 9 + 1 = 0


x^2 - 6x + 10 = 0 ----> Equation in Standard Form: {{{y = x^2 - 6x + 10}}}