Question 728339
{{{y=(1/2)x}}}...here you have a linear function because {{{x^1}}}

to graph this line you will need two points

choose two values for {{{x}}} and calculate {{{y}}}

if {{{x=0}}}...=>..{{{y=(1/2)*0=0}}}

if {{{x=2}}}...=>..{{{y=(1/2)*2=2/2=1}}}

make a table

{{{x}}}|{{{y}}}

{{{0}}}|{{{0}}}

{{{2}}}|{{{1}}}

plot these points and draw a line through:


{{{drawing( 600, 600, -6, 6, -6, 6, x-2,circle(0,0,0.1),circle(2,1,0.1),  graph( 600, 600, -6, 6, -6, 6, (1/2)x)) }}}