Question 63876
7/20: Miss Tumble was administered a Cybex strength test upon arrival.Her quadriceps of the injured leg measured 55 foot-pounds in extension.
7/25: Daily regimen is showing progress. Cybex test measures 90 foot-pounds.
8/1: Some swelling earlier in the week.General reports of less pain. Cybex test measures 140 foot-pounds.
8/6: Less swelling. Range of motion has shown marked increase. Cybex test measures 185 foot-pounds.
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This data gives you four points (day,foot-pound)
The points are (1,55),(6,90),(13,140),(18,185)
Using the two middle points you can find the equation relating 
day and foot-pounds:
slope= [140-90]/[13-6]=50/7
y=intercept: 140=(50/7)(13)+b; b=47.14
EQUATION: y=(50/7)x+47.14
Comment: The four points don't all lie on the same line.  I picked
the two middle points.  You might have picked two others.
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a. Please graph the data above provided by the physical therapist.Let July 20 be represented as Day 1,which makes August 18 Day 30.
Comment: I tried to show you the graph but this software will not display
the line.
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Two consultants were hired to advise the coach. 
Consultant A said that the function F given by the equation f(x)=40+8x approximated the data well. So consultant A predicted that on August 18(Day 30), Miss Tumble would have 280 foot-pounds of strength and would be strong enough to compete.
Consultant B said the function g given by the equation g(x)=55+6x approximated the data well. So consultant B predicted that on August 18(Day 30), Miss Tumble would have only 235 foot-pounds of strength and would not be strong enough to compete.
b.Sketch each consultant's function on the graph you created in question a above. Use a different color pencil or pen for each graph.
Comment: Again I tried to show you the two lines but to no avail.
Hope this helps.
Cheers,
Stan H.