Question 728012
I'll say {{{ z = x - 2/3 }}}
{{{ z^2 = 14 }}}
{{{ z = sqrt( 14 ) }}}
and, also
{{{ z = -sqrt(14) }}}
{{{ x - 2/3 = sqrt(14) }}}
{{{ x = 2/3 + sqrt(14) }}}
and, also
{{{ x = 2/3 - sqrt(14) }}}
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check answer:
{{{ ( 2/3 + sqrt(14) - 2/3 )^2 = 14 }}}
{{{ ( sqrt(14) )^2 = 14 }}}
{{{ 14 = 14 }}}
OK