Question 727968
A random sample of 100 voters found that 42% were going to vote for a certain candidate.  Find the 99% limit for the population proportion of voters who will vote for that candidate.
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p-hat = 0.42
E = z*s/sqrt(pq/n) = 2.5758*sqrt[0.42*0.58/100] = 0.1271
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98% CI: 0.42-0.1271 < p < 0.42+0.1271
Ans: A
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Cheers,
Stan H.
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A)	29.3% < p < 54.7%	C)	32.3% < p < 51.7%
B)	30.8% < p < 53.2%	D)	35.6% < p < 48.4%