Question 727835
a+b=85,
.10a + .04b=.08*85
solve by substitution
b=85-a
.10a+.04(85-a)=.08*85
.10a+.04*85-.04a=.08*85
.06a=.04*85
a=(.04/.06)*85
a=2/3*85
a=56.6667,   b=28.3333