Question 727834
Distance = rate x time.  The plane travels the same distance both ways.  So the original distance = the return distance.<P>
For the original distance, the plane flew at its speed (x) minus 60 MPH (the plane is traveling against the headwind, so the headwind subtracts from the plane's speed). D = (x-60) * 5<P>
For the return trip the tailwind adds to the speed.  The round trip was 9 hours, and the original trip took 5 hours, so the return trip took 9-5 = 4 hours.  D = (x+60) * 4<P>
Those distances are equal.  (x-60)*5 = (x+60)*4 <P>
5x - 300 = 4x + 240<P>
x = 540 MPH
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