Question 727392
1/3pih(r1^2+r2^2) Volume of both cones

which = pir^2h volume of cylinder


{{{pir^2h =pi* 1/3*h(r1^2+r2^2)}}}


{{{r^2=1/3(r1^2+r2^2)}}}

{{{r= sqrt(1/(3(r1^2+r2^2)))}}}