Question 727411
x1	y1	x2	y2									
  1/ 4	- 1/3	- 1/4	-3    									
												
The general equation of the line when co-ordinates of two points are given is												
												
{{{(y-	y1)/(	y1-y2) = (x-x1)/(x1-x2)}}}										
												
{{{(y-	- 1/3	)/(	- 1/3	-	-3    	)=(x-	  1/ 4	)/(	 1/4	-	- 1/4	)}}}
												
												
{{{(y-	  1/ 3	)/(	8/ 3	)=(x+	-  1/ 4	) /(	  1/ 2	)}}}				
												
{{{ 	  1/ 2	(y-	  1/ 3	) =	2  2/ 3	(x-	  1/ 4	)}}}				
												
  1/ 2	y-	  1/ 6	=	8/ 3	x  	  2/ 3						
												
  1/ 2	y=	2  2/ 3	x+	  5/ 6								
/	  1/ 2											
y=	16/ 3	x+	5/ 3	

You may write the equation in the form requested.