Question 727402
287 to base 3
<pre>
We divide 3 into 287, getting 95 with remainder 2. We write the 
quotient 95 below and the remainder 2 out to the side, like this:

3<u>)287</u>
   95 R=2

Under that, we divide 3 into 95, getting 31 with remainder 2. We 
write the quotient 31 below and the remainder 2 out to the side, 
like this:

3<u>)287</u>
 3<u>)95</u> R=2
   31 R=2
  
Under that, we divide 3 into 31, getting 10 with remainder 1.  We
write the quotient 10 below and the remainder 1 out to the side,
like this:

3<u>)287</u>
 3<u>)95</u> R=2
 3<u>)31</u> R=2
   10 R=1

Under that, we divide 3 into 10, getting 13 with remainder 1.  We
write the quotient 3 below and the remainder 1 out to the side,
like this:

3<u>)287</u>
 3<u>)95</u> R=2
 3<u>)31</u> R=2
 3<u>)10</u> R=1
    3 R=1

Under that, we divide 3 into 3, getting 1 with remainder 0.  We
write the quotient 1 below and the remainder 0 out to the side,
like this:

3<u>)287</u>
 3<u>)95</u> R=2
 3<u>)31</u> R=2
 3<u>)10</u> R=1
  3<u>)3</u> R=1
    1 R=0
   
Under that, we divide 3 into 1, getting 0 with remainder 1.  We
write the quotient 0 below and the remainder 1 out to the side,
like this:

3<u>)287</u>
 3<u>)95</u> R=2
 3<u>)31</u> R=2
 3<u>)10</u> R=1
  3<u>)3</u> R=1
  3<u>)1</u> R=0
    0 R=1

We are done since the last quotient was 0.

To get the number 287 in base 3, we write
the remainders from bottom to top:

287 in base ten equals 101122 in base 3.

Edwin</pre>