Question 1430
(z-8)(z+4) = -35
So we should multiply (z-8) by (z+4) first
z^2-4z-32 = -35
Now add 35 to both sides
z^2-4z+3 = 0
Now factor
(z-1)(z-3) = 0
Now solve for z
z = 1 or 3