Question 726916
-b/2a gives the x-coordinate of the vertex of the parabola with general equation {{{ax^2 + bx + c = f(x)}}}<P>
In this problem a=2 and b=-8 so the x-coordinate of the vertex is -(-8)/2*(2) = 2.<P>
Plug 2 into the equation to find the y-coordinate of the vertex.<P>
2(2)^2 -8*(2) + 7 = 2*4-16+7 = -1<P>
The vertex is (2,-1)
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