Question 726913
Call the integers x, x+2 and x+4  (the difference between consecutive odd integers is always 2.)<P>
x is the least, and x+4 is the greatest, and their product is x(x+4) = {{{x^2 + 4x}}}<P>
That product is 16 more than the middle integer, x+2 or it = x+2+16<P>
{{{x^2 + 4x = x+18}}} <P>
{{{x^2 + 3x -18 =0}}}<P>
(x+6)(x-3) = 0 so x=-6 and x=3<P>
-6 is even, so x=3 and the integers are 3, 5, and 7<P>Hope the solution helped.  Sometimes you need more than a solution.  Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)