Question 726629
I assume this is the initial equation:
{{{(sin(theta)cos(theta))/(cos(theta)-cos^3(theta))}}}

{{{
(sin(theta)cos(theta))/(cos(theta)-cos^3(theta))
=(sin(theta)cos(theta))/(cos(theta))(1-cos^2(theta))
= sin(theta)/sin^2(theta)
= 1/sin(theta)
= csc(theta)
}}}