Question 63784
Log(base of 2)(4x)= 5-Log(base of 2)(x-2)

or Log(base of 2)(4x) + Log(base of 2)(x-2) = 5

or Log(base of 2)(4x)(x-2)=Log(base of 2)(2^5)[we know Loga + logb=logab  base r same]

or  4x(x-2)= 2^5=32

or  x^2 -2x =  32/4 =8[factorize the equn]

or   x^2 -2x -8 =0

or   x^2 -4x +2x -8 =0

or  x(x-4) +2(x-4) =0

or  (x-4)(x+2)=0
 then either (x-4) =0
         ie x=4

or x+2 =0
x=-2