Question 726614
 If the width of a rectangle is 5 meters less than the length and the perimeter of the rectangle is 53 meters, find the length and width.
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Let length be "x".
Then width is "x-5"
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Perimeter = 2(length + width)
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53 = 2(x + x-5)
53 = 2(2x-5)
53 = 4x-10
4x = 63
x = 15.75 meters (length)
x-5 = 10.75 meters (width)
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Cheers,
Stan H.
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