Question 726608
 {{{ (x^3+64)/(2x^2+8x)}}}


 {{{ (x^3+4^3)/(2x^2+8x)}}}...recall the rule for factoring the sum of cubes: {{{a^3+b^3 =(a+b)(a^2-ab+b^2)}}} 


{{{((x+4)(x^2-4x+16))/2x(x+4)}}}..simplify


{{{(cross((x+4))(x^2-4x+16))/2xcross((x+4))}}}


{{{(x^2-4x+16)/2x}}}