Question 726604
if the Base is {{{b=2 (1/3)yd}}} and the Height is {{{h=(3/5) yd}}}, than the area will be

{{{A=bh/2}}}

{{{A=(2(1/3)yd)((3/5)yd)/2}}}

{{{A=((2*3+1)/3)yd((3/5)yd)/2}}}

{{{A=(7/3)yd((3/5)yd)/2}}}

{{{A=((7/cross(3))yd)((cross(3)/5)yd)/2}}}

{{{A=((7/5)yd^2)/2}}}

{{{A=(7/10)yd^2}}}