Question 726051
What are the foci of the ellipse? Graph the ellipse 
x^2/49 + y^2/64 =1
This is an equation of an ellipse with vertical major axis.
Its standard form: {{{(x-h)^2/b^2+(y-k)^2/a^2=1}}}, a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
center: (0,0)
a^2=64
b^2=49
c^2=a^2-b^2=64-49=15
c=√15≈3.9
foci: (0±c,0)=(0±3.9,0)=(-3.9,0) and (3.9,0)

see graph below:
y=±(64-64x^2/49)^.5

{{{ graph( 300, 300, -10, 10, -10, 10,(64-64x^2/49)^.5,-(64-64x^2/49)^.5) }}}